Query 1,2,5

P3/queries/query1.sql

@@ -1,17 +1,12 @@
+-- Author: Anatole Huet
+
 -- Determine the 10 countries with the most purchases; list the names of these countries, as well as the number of purchases; sort the results in decreasing order of purchases.
 
-SELECT name, cnt
+SELECT Country.name, COUNT(Purchases.id) as cnt
-FROM (
+FROM Purchases
-	SELECT country, sum(qty) as cnt
+    JOIN Province ON Purchases.province = Province.rowid
-	FROM (
+    JOIN Country ON Province.country = Country.code
-		SELECT province, sum(qty) as qty
+GROUP BY Country.name
-		FROM Purchases
+ORDER BY cnt DESC
-		GROUP BY province
+LIMIT 10
-	)
-	JOIN province ON province = province.ROWID
-	GROUP BY country
-	ORDER BY cnt DESC
-	LIMIT 10
-)
-JOIN COUNTRY on country == code
 ;

P3/queries/query2.sql

@@ -1,6 +1,8 @@
+-- Author: Anatole Huet
+
 -- Determine the total number of purchases for each product. List the number of the product, as well as the total number of purchases.
 
-SELECT product, sum(qty) as cnt
+SELECT product, Count(*) as cnt
 FROM Purchases
 GROUP BY product
 ;

P3/queries/query5.sql

@@ -0,0 +1,9 @@
+-- Author: Anatole Huet
+
+-- Determine the total number of purchases for each product. List the number of the product, as well as the total number of purchases.
+
+SELECT product, Count(*) as cnt
+FROM Purchases
+where time > date((SELECT MAX(time) FROM Purchases),'-10 days')
+GROUP BY product
+;