linfo2335-programming-parad.../project-3/regex/code/code497.py

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Python
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2024-05-23 14:47:20 +02:00
def approx_pi(i):
i = 5
if i == 0:
return 4
else:
if i == 1:
return 2.666666666
else:
if i == 2:
return 3.46666666
else:
if i == 3:
return 2.8952381
else:
pi = 0
for j in range(i+1) :
pi += (((-1)**j) / ((2*j)+1))
print(4*pi)