linfo2335-programming-parad.../project-3/regex/code/code2177.py

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2024-05-23 14:47:20 +02:00
def approx_pi(i):
if i == 0:
return 4
else:
if i == 1:
return 2.666666666
else:
if i == 2:
return 3.46666666
else:
if i == 3:
return 2.8952381
else:
pi = 0
for j in range(i+1) :
pi += (((-1)**pi) / ((2*pi)+1))
return(4*pi)